1864 United States presidential election in Pennsylvania
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Elections in Pennsylvania |
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Government |
The 1864 United States presidential election in Pennsylvania took place on November 8, 1864, as part of the 1864 United States presidential election. Voters chose 26 representatives, or electors to the Electoral College, who voted for President and Vice President.
Pennsylvania voted for the National Union candidate, Abraham Lincoln, over the Democratic candidate, George B. McClellan. Lincoln won Pennsylvania by a margin of 3.5%.
Results
United States presidential election in Pennsylvania, 1864[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
National Union | Abraham Lincoln | 296,391 | 51.75% | 26 | |
Democratic | George B. McClellan | 276,316 | 48.25% | 0 | |
Totals | 572,707 | 100.0% | 26 |
References
- ^ "1864 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved 3 August 2012.