1912 United States presidential election in Pennsylvania

Main article: United States presidential election, 1912

United States presidential election in Pennsylvania, 1912

November 5, 1912

Nominee Theodore Roosevelt Woodrow Wilson Party Progressive Democratic Home state New York New Jersey Running mate Hiram Johnson Thomas R. Marshall Electoral vote 38 0 Popular vote 444,894 395,637 Percentage 36.53% 32.49%   Nominee William Howard Taft Eugene Victor Debs Party Republican Socialist Home state Ohio Indiana Running mate Nicholas M. Butler (replaced James S. Sherman) Emil Seidel Electoral vote 0 0 Popular vote 273,360 83,614 Percentage 22.45% 6.87%

County results* *Red denotes a Taft victory—Debs did not carry any counties

President before election William Howard Taft Republican Elected President Woodrow Wilson Democratic

The 1912 United States presidential election in Pennsylvania took place on November 5, 1912 throughout the continuous 48 states. This was the first time that Arizona and New Mexico took part in a presidential election having been admitted to the Union earlier in the year. Voters chose 38 representatives, or electors to the Electoral College, who voted for President and Vice President.

This election was a four-way contest. Pennsylvania voted for the Progressive nominee former President Theodore "Teddy" Roosevelt over the Democratic nominee New Jersey Governor Woodrow Wilson, Republican nominee President William Howard Taft, and Socialist Party of America nominee union leader Eugene V. Debs. Roosevelt won Pennsylvania by a margin of 4.04%.

Results

United States presidential
Party		Candidate	Votes	Percentage	Electoral votes
	Progressive	Theodore Roosevelt	444,894	36.53%	38
	Democratic	Woodrow Wilson	395,637	32.49%	0
	Republican	William Howard Taft	273,360	22.45%	0
	Socialist	Eugene V. Debs	83,614	6.87%	0
	Prohibition	Eugene Chafin	19,525	1.60%	0
	Socialist Labor	Arthur Reimer	706	0.06%	0