Talk:Heisenberg picture

Physics Start‑class High‑importance

	Physics portal This article is within the scope of WikiProject Physics, a collaborative effort to improve the coverage of Physics on Wikipedia. If you would like to participate, please visit the project page, where you can join the discussion and see a list of open tasks.PhysicsWikipedia:WikiProject PhysicsTemplate:WikiProject Physicsphysics articles
Start	This article has been rated as Start-class on Wikipedia's content assessment scale.
High	This article has been rated as High-importance on the project's importance scale.

Article is too technical

I've added the technical tag, as this article seems to be too technical. There's no introduction to the subject, and it launches into the mathematical formulism without too much background. I'm tempted to add a "clean up" tag as well, as the article seems somewhat confusing and hard to follow. Thoughts? Privong 17:25, 24 August 2005 (UTC)[reply]

I agree that the article is too advanced for the casual reader. But this is organized in as orderly a way as mathematics will allow. I will add an introduction and a brief historical section and remove the tag. Beyond the history of Matrix mechanics nothing can be said about it without "advanced" mathematics. Such is the nature of quantum physics. --Hfarmer 18:09, 25 August 2005 (UTC)[reply]

Yea. I agree that, by the nature of the topic it's very technical. I was more looking for an introduction like the one you provided, so that the casual reader could at least get a sense of what the Heisenberg picture is, even if they don't understand the mathematics behind it. Thanks for adding the introduction! Privong 15:13, 1 September 2005 (UTC)[reply]

To the original Author of the page I feel it would be best to give a more basic but mathematical presentation of the matterial. By more basic what I mean is a presentation of how to solve for the state vector given the Hamiltonian operator of the interaction. I will work on this and add such a section latter. --Hfarmer 18:42, 25 August 2005 (UTC)[reply]

Redirecting

I am moving this material over to Matrix mechanics. There is no need for two articles and the topic is more commonly known by that name. DV8 2XL 20:50, 2 November 2005 (UTC)[reply]

I probably don't agree with that. Matrix mechanics is really just a historical theory these days, whereas the Heisenberg picture is still used and discussed. -Lethe | Talk 06:44, 3 November 2005 (UTC)

I also disagree. The Heisenberg picture and Schrodinger picture (and the interaction picture) are different from any distinction between matrix mechanics and wave mechanics. --MarSch 13:00, 3 November 2005 (UTC)[reply]

Why isn't the equation given for...?

Heisenberg's quote "famous 'commutation relation' for the quantization condition that is at the basis of quantum mechanics" as shown on the web page:

[1]

I can't add it because I don't know how to make the math symbols, but I think it is important because it shows the difference between the Fourier series of amplitudes of position and momentum not to commute by a value of h/2pi. (h-bar) of intensity.--Voyajer 02:36, 27 December 2005 (UTC)[reply]

About the formalism

Hi. I've noticed that this article's author have used Schrödinger equation to derive Heisenberg's. But as long as heisenberg's picture of quantum mechanics is complete by it's own, this is not really necessary...

I agree, deriving the Heisenberg picture from the Schrodinger picture doesn't make any more sense than deriving the Schrodinger picture from the Heisenberg picture. The article assumes there's something fundimental about attaching time dependence to psi, rather than the operator, and their isn't. Maybe somebody can replace this with something better. —Preceding unsigned comment added by 128.211.179.162 (talk) 22:58, 30 June 2010 (UTC)[reply]

Somewhat Circular

The derivation, is somewhat circular. Also, interestingly, there is no mention of where the (del A / del t)classical comes from, and, as it appears in the derivation, I think its wrong! Not to say its wrong but it comes up differently I think. —Preceding unsigned comment added by 131.94.41.41 (talk) 13:21, 4 January 2008 (UTC)[reply]

Lorentz invariance

"Lorentz invariance is manifest in the Heisenberg picture."

Really? Like the Schrödinger equation, the Heisenberg equation has first order derivatives in t and second order derivatives in space ( $H=-{\frac {\hbar ^{2}}{2m}}\nabla ^{2}$ ), which doesn't look too good. I think this could use some backing up. 195.37.186.62 (talk) 03:05, 15 September 2010 (UTC)[reply]