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2018 Brownlow Medal

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2018 Brownlow Medal
2018 Brownlow Medalist, Tom Mitchell
Date24 September
LocationCrown Palladium
Hosted byBruce McAvaney
WinnerTom Mitchell (Hawthorn)
(28 votes)
Television/radio coverage
NetworkSeven Network
Telstra
← 2017 · Brownlow Medal · 2019 →

The 2018 Brownlow Medal was the 91st year the award was presented to the player adjudged the fairest and best player during the Australian Football League (AFL) home and away season.[1] Tom Mitchell of the Hawthorn Football Club won the medal with 28 votes.

Leading votegetters

Player Votes
1st Tom Mitchell (Hawthorn) 28
2nd Steele Sidebottom (Collingwood) 24
3rd Angus Brayshaw (Melbourne) 21
=4th Patrick Cripps (Carlton) 20
Max Gawn (Melbourne)
=6th Rory Laird (Adelaide) 19
Dustin Martin (Richmond)
=8th Jack Steven (St Kilda) 18
Dayne Beams (Brisbane Lions)
10th Brodie Grundy (Collingwood) 17

Voting procedure

The three field umpires (those umpires who control the flow of the game, as opposed to goal or boundary umpires) confer after each match and award three votes, two votes and one vote to the players they regard as the best, second best and third best in the match, respectively. The votes are kept secret until the awards night, and are read and tallied on the evening.[2]

References

  1. ^ Lovett, Michael (ed.). AFL Record Season Guide 2016. Docklands, Victoria: Slattery Media Group. p. 593.
  2. ^ "Brownlow Medal history and winners - AFL.com.au". afl.com.au. Retrieved 27 August 2018.