1828 United States presidential election in Maryland
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| Elections in Maryland |
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 Government |
The 1828 United States presidential election in Maryland took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose 11 representatives, or electors to the Electoral College, who voted for President and Vice President.
Maryland voted for the National Republican candidate, John Quincy Adams, over the Democratic candidate, Andrew Jackson. Adams won Maryland by a margin of 0.5%.
Results
| 1828 United States presidential election in Maryland[1] | |||||
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| Party | Candidate | Votes | Percentage | Electoral votes | |
| National Republican | John Quincy Adams | 23,014 | 50.25% | 6 | |
| Democratic | Andrew Jackson | 22,782 | 49.75% | 5 | |
| Totals | 45,796 | 100.0% | 11 | ||
See also
References
- ^ "1828 Presidential General Election Results - Maryland". U.S. Election Atlas. Retrieved 28 February 2013.
State and district results of the 1828 United States presidential election | ||
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