1884 United States presidential election in Illinois

Main article: 1884 United States presidential election

1884 United States presidential election in Illinois

November 4, 1884

Nominee James G. Blaine Grover Cleveland Party Republican Democratic Home state Maine New York Running mate John A. Logan Thomas A. Hendricks Electoral vote 22 0 Popular vote 337,469 312,351 Percentage 50.17% 46.43%

County Results Blaine   40-50%   50-60%   60-70%   70-80% Cleveland   40-50%   50-60%   60-70% Tie   <50%

President before election Chester A. Arthur Republican Elected President Grover Cleveland Democratic

The 1884 United States presidential election in Illinois took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose 22 representatives, or electors to the Electoral College, who voted for president and vice president.

Illinois voted for the Republican nominee, James G. Blaine, over the Democratic nominee, Grover Cleveland. Blaine won the state by a narrow margin of 3.74%.

Results

1884 United States presidential election in Illinois
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Republican	James Gillespie Blaine of Maine	John Alexander Logan of Illinois	337,469	50.17%	22	100.00%
	Democratic	Grover Cleveland of New York	Thomas Andrews Hendricks of Indiana	312,351	46.43%	0	0.00%
	Prohibition	John Pierce St. John of Kansas	William Daniel of Maryland	12,074	1.79%	0	0.00%
	Greenback	Benjamin Franklin Butler of Massachusetts	Absolom Madden West of Mississippi	10,776	1.60%	0	0.00%
Total				672,670	100.00%	22	100.00%

See also

• United States presidential elections in Illinois