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The 1992 United States presidential election in Wisconsin took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose eleven representatives, or electors to the Electoral College, who voted for president and vice president.
Wisconsin was won by Governor Bill Clinton (D-Arkansas) with 41.13% of the popular vote over incumbent President George H. W. Bush (R-Texas) with 36.78%. Businessman Ross Perot (I-Texas) finished in third, with 21.51% of the popular vote.[1] Clinton ultimately won the national vote, defeating incumbent President Bush.[2] As of the 2016 presidential election[update], this is the last election in which Florence County voted for the Democratic candidate.
Results
1992 United States presidential election in Wisconsin[1]
|
Party
|
Candidate
|
Votes
|
Percentage
|
Electoral votes
|
|
Democratic
|
William Jefferson Clinton
|
1,041,066
|
41.13%
|
11
|
|
Republican
|
George Herbert Walker Bush
|
930,855
|
36.78%
|
0
|
|
Independent
|
Henry Ross Perot
|
544,479
|
21.51%
|
0
|
|
Libertarian
|
Andre Verne Marrou
|
2,877
|
0.11%
|
0
|
|
America First
|
James "Bo" Gritz
|
2,311
|
0.09%
|
0
|
|
Peace and Freedom
|
Ronald Daniels
|
1,833
|
0.07%
|
0
|
|
Taxpayers’
|
Howard Phillips
|
1,772
|
0.07%
|
0
|
|
Independent
|
J. Quinn Brisben
|
1,211
|
0.05%
|
0
|
|
Natural Law
|
Dr. John Hagelin
|
1,070
|
0.04%
|
0
|
|
Other write-ins
|
|
961
|
0.04%
|
0
|
|
New Alliance Party
|
Lenora Fulani
|
654
|
0.03%
|
0
|
|
Democrats for Economic Recovery
|
Lyndon LaRouche
|
633
|
0.02%
|
0
|
|
Independent
|
Jack Herer
|
547
|
0.02%
|
0
|
|
Socialist Workers Party
|
James Warren
|
390
|
0.02%
|
0
|
|
Independent
|
Roland Hem (write-in)
|
405
|
0.02%
|
0
|
Totals
|
2,531,114
|
100.0%
|
11
|
References