Douglas, Iowa
Douglas, Iowa | |
|---|---|
  Douglas Location of Douglas within the state of Iowa | |
| Coordinates: 43°00′30″N 91°52′17″W / 43.00833°N 91.87139°W[1] | |
| Country |  United States |
| State |  Iowa |
| County | Fayette County |
| Elevation | 297 m (974 ft) |
| Time zone | UTC-6 (Central (CST)) |
| • Summer (DST) | UTC-5 (CDT) |
| GNIS feature ID | 463549[1] |
Douglas is an unincorporated community in Fayette County, Iowa, United States. It is located near the junction of County Road B44 and Maple Road, three miles southwest of Eldorado.[1]
History
[edit]
Douglas was originally spelled Douglass. The population of the community was 216 in 1902,[2] and was 105 in 1925.[3] The population was 40 in 1940.[4]
References
[edit]- ^ a b c d U.S. Geological Survey Geographic Names Information System: Douglas, Iowa
- ^ Cram's Modern Atlas: The New Unrivaled New Census Edition. J. R. Gray & Company. 1902. pp. 203–207.
- ^ Premier Atlas of the World: Containing Maps of All Countries of the World, with the Most Recent Boundary Decisions, and Maps of All the States, territories, and Possessions of the United States with Population Figures from the Latest Official Census Reports, Also Data of Interest Concerning International and Domestic Political Questions. Rand McNally & Company. 1925. p. 190.
- ^ The Attorneys List. United States Fidelity and Guaranty Company, Attorney List Department. 1940. p. 298.
Municipalities and communities of Fayette County, Iowa, United States | ||
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| Cities |  | |
| Townships | ||
| Unincorporated communities | ||
| Footnotes | ‡This populated place also has portions in an adjacent county or counties | |