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Hickory Grove Township, Benton County, Indiana

Coordinates: 40°31′06″N 87°28′47″W / 40.51833°N 87.47972°W / 40.51833; -87.47972
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Hickory Grove Township
Township
Location of Hickory Grove Township in Benton County
Location of Hickory Grove Township in Benton County
Coordinates: 40°31′06″N 87°28′47″W / 40.51833°N 87.47972°W / 40.51833; -87.47972
CountryUnited States
StateIndiana
CountyBenton
OrganizedMarch 1876
Government
 • TypeIndiana township
Area
 • Total
28.9 sq mi (75 km2)
 • Land28.9 sq mi (75 km2)
 • Water0 sq mi (0 km2)
Elevation
[1]
745 ft (227 m)
Population
 (2010)
 • Total
409
 • Density14.2/sq mi (5.5/km2)
Time zoneUTC-5 (EST)
 • Summer (DST)UTC-4 (EDT)
FIPS code18-33358[2]
GNIS feature ID453410

Hickory Grove Township is one of eleven townships in Benton County, Indiana. As of the 2010 census, its population was 409 and it contained 172 housing units.[3] It was organized in March 1876 and named for a grove of hickory trees that grew within its borders in the 19th century.[4]

Geography

According to the 2010 census, the township has a total area of 28.9 square miles (75 km2), all land.[3]

Cities and towns

Unincorporated towns

Adjacent townships

Major highways

Cemeteries

The township contains one cemetery, Totheroh.

References

  • "Hickory Grove Township, Benton County, Indiana". Geographic Names Information System. United States Geological Survey, United States Department of the Interior. Retrieved 2009-09-24.
  • United States Census Bureau cartographic boundary files
  1. ^ "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.
  2. ^ "American FactFinder". United States Census Bureau. Retrieved 2008-01-31.
  3. ^ a b "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Retrieved 2013-05-10.
  4. ^ Birch, Jesse Setlington (1942) [1928]. History of Benton County and Historic Oxford. Oxford, Indiana: Craw & Craw, Inc. p. 21.
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