The Riemann–Lebesgue lemma holds in a variety of other situations.
- If ƒ is L1 integrable and supported on (0, ∞), then the Riemann–Lebesgue lemma also holds for the Laplace transform of ƒ. That is,
- as |z| → ∞ within the half-plane Re(z) ≥ 0.
- A version holds for Fourier series as well: if ƒ is an integrable function on an interval, then the Fourier coefficients of ƒ tend to 0 as n → ±∞,
- This follows by extending ƒ by zero outside the interval, and then applying the version of the lemma on the entire real line.
The Riemann–Lebesgue lemma can be used to prove the validity of asymptotic approximations for integrals. Rigorous treatments of the method of steepest descent and the method of stationary phase, amongst others, are based on the Riemann–Lebesgue lemma.
If ƒ is an arbitrary integrable function, it may be approximated in the L1 norm by a compactly supported smooth function g. Pick such a g so that ||ƒ − g||L1 < ε. Then
and since this holds for any ε > 0, the theorem follows.
The case of non-real t.[clarification needed]
Assume first that ƒ has a compact support on and that ƒ is continuously differentiable. Denote the Fourier/Laplace transforms[which?] of ƒ and by F and G, respectively. Then , hence as . Because the functions of this form are dense in , the same holds for every ƒ.