Talk:Form factor (electronics)

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Physics Mid‑importance

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Electrical engineering Mid‑importance

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I deleted the following from the page because I believe it's nonsense (the RMS is the DC equivalent, not the form factor). I've preserved it here in case it was valuable to someone. LightYear (talk) 22:42, 12 December 2012 (UTC)[reply]

The form factor can be multiplied by an alternating current's peak voltage or current to provide the direct current equivalent in terms of power.

$k_{f}U_{AC}=U_{DC}$ and $k_{f}I_{AC}=I_{DC}$ .
Conversely, it can be used to divide a DC value, giving the peak AC value needed to provide the same power.
${\frac {U_{DC}}{k_{f}}}=U_{DC}{\frac {X_{arv}}{X_{rms}}}=U_{AC}$

What is best methods for solving alternating current problem

I need a book Apjdiehard98 (talk) 16:02, 18 February 2017 (UTC)[reply]