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That's what the description unter the map currently says, but the number cannot be anywhere near correct, it's far too small: 4 mio gallons equals approximately 18000 m³. The width of the Strangford Narrows is about 400 meters. In the middle, near the SeaGen, the water depth is more than 25 meters, and the max flow velocity is about 5 knots (2.4 m/s). Even with an average depth of only 2 meters across the narrows and an average flow velocity of only 1 knot across the narrows that would be more than 18000 m³ per minute. The total amount of water per tide must be well over a billion gallons. Maybe the text should read "4 billion gallons of water flow in and out of Strangford Lough twice a day"? --Tetris L (talk) 20:24, 10 February 2009 (UTC)[reply]
I concur. I calculate that under the assumptions of: the average velocity of the water is 1 knot, 400m length, an average of 2m depth, and that a single tide lasts 9 hours - I obtain 3.3 billion gallons per tide. The assumptions of course must be corrected, but the listed value is an order of 10 off which indicates an error either on the part of us or on that source's value. --71.12.2.110 (talk) 17:44, 24 December 2009 (UTC)[reply]