1880 United States presidential election in Alabama
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| Turnout | 12.03% of the total population  5.19 pp[1] | |||||||||||||||||||||||||
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| Elections in Alabama |
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 Government |
The 1880 United States presidential election in Alabama took place on November 2, 1880, as part of the 1880 United States presidential election. Alabama voters chose ten representatives, or electors, to the Electoral College, who voted for president and vice president[2].
Alabama was won by General Winfield Scott Hancock (D–Pennsylvania), running with former Representative William Hayden English, with 59.99% of the popular vote, against Representative James Garfield (R-Ohio), running with the 10th chairman of the New York State Republican Executive Committee Chester A. Arthur, with 37.10% of the vote.[2]
Results
| United States presidential election in North Carolina, 1868[2] | ||||||||
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| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Winfield Scott Hancock of Pennsylvania | William Hayden English of Indiana | 91,130 | 59.99% | 10 | 100.00% | ||
| Republican | James Garfield of Ohio | Chester A. Arthur of New York | 56,350 | 37.10% | 0 | 0.00% | ||
| Greenback | James B. Weaver of Iowa | Barzillai J. Chambers of Texas | 4,422 | 2.91% | 0 | 0.00% | ||
| Total | 151,902 | 100.00% | 10 | 100.00% | ||||
References
- ^ "1884 Presidential Election Results Alabama Total Population Turnout".
{{cite web}}: Cite has empty unknown parameter:|1=(help) - ^ a b c "1880 Presidential Election Results Alabama".
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