1884 United States presidential election in Minnesota

United States presidential election in Minnesota, 1884
Blaine 50-60% 60-70% 70-80% 80-90% >90%	Cleveland 50-60% 60-70%
President before election; Chester A. Arthur; Republican	Elected President ; Grover Cleveland; Democratic

The 1884 Presidential Election held in Minnesota took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president.

Minnesota was won by Republican nominee, James G. Blaine, over the Democratic nominee, Grover Cleveland. Blaine won the state by a margin of 21.91%.

With 58.78% of the popular vote, Minnesota would prove to be Blaine's second strongest victory in terms of percentage in the popular vote after Vermont^[1].

Results

United States presidential election in Minnesota, 1884^[2]
Party		Candidate	Running mate	Popular vote		Electoral vote
Party		Candidate	Running mate	Count	%	Count	%
	Republican	James Gillespie Blaine of Maine	John Alexander Logan of Illinois	111,685	58.78%	7	100.00%
	Democratic	Grover Cleveland of New York	Thomas Andrews Hendricks of Indiana	70,065	36.87%	0	0.00%
	Prohibition	John Pierce St. John of Kansas	William Daniel of Maryland	4,684	2.47%	0	0.00%
	Greenback	Benjamin Franklin Butler of Massachusetts	Absolom Madden West of Mississippi	3,583	1.89%	0	0.00%
Total				190,017	100.00%	7	100.00%

References

^ "1884 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
^ "1884 Presidential General Election Results - Minnesota". U.S. Election Atlas. Retrieved 23 December 2013.

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[1] "1884 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.

[results-2] "1884 Presidential General Election Results - Minnesota". U.S. Election Atlas. Retrieved 23 December 2013.

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