1788–89 United States presidential election in New Hampshire

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United States presidential election in New Hampshire, 1789

December 15, 1788 – January 10, 1789 1792 →
 
Nominee George Washington John Adams
Party Nonpartisan Federalist
Home state Virginia Massachusetts
Electoral vote 5 5
Popular vote 5,909
Percentage 100%

The 1789 United States presidential election in New Hampshire took place between December 15, 1788 and January 10, 1789, as part of the 1788–1789 United States presidential election to elect the first President. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.

New Hampshire unanimously voted for nonpartisan candidate and commander-in-chief of the Continental Army, George Washington. The total vote is composed of 5,909 for Federalist electors, all of whom were supportive of Washington.[1]

Results

United States presidential election in New Hampshire, 1789
Party Candidate Votes Percentage Electoral votes
Nonpartisan George Washington 5,909 100% 5
Totals 5,909 100.0% 5

References

  1. ^ Cite error: The named reference results was invoked but never defined (see the help page).