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1889 Chicago mayoral election

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1889 Chicago mayoral election
← 1887 April 2, 1889 1891 →
 
Nominee DeWitt Clinton Cregier John A. Roche
Party Democratic Republican
Popular vote 57,340 46,328
Percentage 54.93% 44.38%

Mayor before election

John A. Roche
Republican

Elected mayor

DeWitt Clinton Cregier
Democratic

In the Chicago mayoral election of 1889, Democrat DeWitt Clinton Cregier defeated incumbent Republican John A. Roche, winning a majority of the vote and a margin of victory in excess of ten percent.

The election was held on April 2, 1889.[1][2]

Campaign

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Cregier backed strongly by trade unions.[3] John Peter Altgeld threw his backing behind Cregier's candidacy.[3]

Results

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1889 Chicago mayoral election[1]
Party Candidate Votes %
Democratic DeWitt Clinton Cregier 57,340 54.93
Republican John A. Roche (incumbent) 46,328 44.38
Prohibition Ira J. Mason 410 0.39
Socialist Labor Charles Orchardson 303 0.29
Turnout 104,381

Creiger received 76.86% of the Polish-American vote, while Roche received 23.07%.[4]

References

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  1. ^ a b The Chicago Daily News Almanac and Year Book for 1912. Chicago Daily News, Incorporated. 1911. p. 464. Retrieved May 12, 2020.
  2. ^ Currey, Josiah Seymour (1912). Chicago: Its History and Its Builders, a Century of Marvelous Growth. S. J. Clarke publishing Company. p. 335.
  3. ^ a b Kersten, Andrew E. (2011). Clarence Darrow: American Iconoclast. Macmillan. p. 46. ISBN 978-0-8090-9486-8. Retrieved June 2, 2020.
  4. ^ Kantowicz, Edward (1972). "The Emergence of the Polish-Democratic Vote in Chicago". Polish American Studies. 29 (1/2): 67–80. JSTOR 20147849.