1940 U.S. National Championships – Women's Singles

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Women's Singles
1940 U.S. National Championships
ChampionUnited States Alice Marble[1]
Runner-upUnited States Helen Jacobs
Final score6–2, 6–3
Details
Draw55
Seeds7
Events
Singles men women
Doubles men women
← 1939 · U.S. National Championships · 1941 →

First-seeded Alice Marble defeated second-seeded Helen Jacobs 6–2, 6–3 in the final to win the Women's Singles tennis title at the 1940 U.S. National Championships. The tournament was played on outdoor grass courts and held from September 2, through September 7, 1940 at the West Side Tennis Club in Forest Hills, Queens, New York.[1]

The draw consisted of 55 players of which seven were seeded.

Seeds[edit]

The eight seeded U.S. players are listed below. Alice Marble is the champion; others show in brackets the round in which they were eliminated.

  1. United States Alice Marble (Champion)
  2. United States Helen Jacobs (Finalist)
  3. United States Pauline Betz (Quarterfinalist)
  4. United States Dorothy Bundy (Quarterfinalist)
  5. United States Sarah Cooke (Third round)
  6. United States Helen Bernard (Quarterfinalist)
  7. United States Virginia Wolfenden (Quarterfinalist)

Draw[edit]

Final eight[edit]

Quarterfinals Semifinals Finals
               
2 United States Helen Jacobs 3 6 6
United States Virginia Wolfenden 6 4 1
2 United States Helen Jacobs 2 6 6
United Kingdom Mary Hardwick 6 1 4
3 United States Pauline Betz 7 1 2
United Kingdom Mary Hardwick 5 6 6
2 United States Helen Jacobs 2 3
1 United States Alice Marble 6 6
1 United States Alice Marble 6 6
6 United States Helen Bernhard 2 3
1 United States Alice Marble 6 6
United Kingdom Valerie Scott 3 3
4 United States Dorothy Bundy 6 4 3
United Kingdom Valerie Scott 2 6 6

References[edit]

  1. ^ a b Collins, Bud (2016). The Bud Collins History of Tennis (3rd ed.). New York: New Chapter Press. p. 499. ISBN 978-1-937559-38-0.