1956 U.S. National Championships – Women's Singles
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| Women's Singles | |
|---|---|
| 1956 U.S. National Championships | |
| Champion |  Shirley Fry[1] |
| Runner-up | Althea Gibson[1] |
| Final score | 6–3, 6–4 |
First-seeded Shirley Fry defeated Althea Gibson 6–3, 6–4 in the final to win the Women's Singles tennis title at the 1956 U.S. National Championships.[2][3]
Contents
Seeds[edit]
The seeded players are listed below. Shirley Fry is the champion; others show in brackets the round in which they were eliminated.
Shirley Fry (Champion)- Althea Gibson (Finalist)
- Louise Brough (Quarterfinalist)
- Dorothy Knode (Quarterfinalist)
- Margaret duPont (Quarterfinalist)
Shirley Bloomer (Semifinalist)- Betty Pratt (Semifinalist)
- Darlene Hard (Quarterfinalist)
Draw[edit]
Key[edit]
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- r. = retired
Final Eight[edit]
| Quarterfinals | Semifinals | Finals | ||||||||||||||||||
| 1 | Shirley Fry
| 6 | 4 | 6 | ||||||||||||||||
| 5 | Margaret duPont
| 2 | 6 | 3 | ||||||||||||||||
| 1 | Shirley Fry
| 6 | 6 | |||||||||||||||||
| 6 |  Shirley Bloomer
| 4 | 4 | |||||||||||||||||
| 6 | Shirley Bloomer
| 6 | 6 | |||||||||||||||||
| 3 | Louise Brough
| 3 | 3 | |||||||||||||||||
| 1 | Shirley Fry
| 6 | 6 | |||||||||||||||||
| 2 | Althea Gibson
| 3 | 4 | |||||||||||||||||
| 4 | Dorothy Knode
| 6 | 0 | 2 | ||||||||||||||||
| 7 | Betty Pratt
| 4 | 6 | 6 | ||||||||||||||||
| 8 | Betty Pratt
| 1 | 8 | |||||||||||||||||
| 2 | Althea Gibson
| 6 | 10 | |||||||||||||||||
| 8 | Darlene Hard
| 7 | 1 | |||||||||||||||||
| 2 | Althea Gibson
| 9 | 6 | |||||||||||||||||
References[edit]
- ^ a b Collins, Bud (2010). The Bud Collins History of Tennis (2nd ed.). [New York City]: New Chapter Press. p. 471. ISBN 978-0942257700.
- ^ G.P. Hughes, ed. (1957). Dunlop Lawn Tennis Annual 1957. London: Ed. J. Burrow & Co. Ltd. pp. 245–247.
- ^ "National Tennis Championships Opens Today". The Free Lance-Star. AP. August 31, 1956. p. 12.
