1860 United States presidential election in Illinois
 | ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
.jpg)
| Elections in Illinois |
|---|
 |
The 1860 United States presidential election in Illinois took place on November 6, 1860, as part of the 1860 United States presidential election. Illinois voters chose 11 representatives, or electors, to the Electoral College, who voted for president and vice president.
Illinois was won by the former congressman Abraham Lincoln (Whig–Illinois), running as a Republican with Senator Hannibal Hamlin, with 50.69% of the popular vote, against Senator Stephen A. Douglas (D–Illinois), running with 41st Governor of Georgia Herschel V. Johnson, with 47.17% of the popular vote.
Liberty Party (under the name Union Party[1]) candidate Gerrit Smith received 35 of his 171 popular votes in Illinois alone. The other 136 votes came from Ohio.[2]
Results
| 1860 United States presidential election in Illinois[3] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Republican | Abraham Lincoln of Illinois | Hannibal Hamlin of Maine | 172,171 | 50.69% | 11 | 100.00% | ||
| Democratic | Stephen A. Douglas of Illinois | Herschel Vespasian Johnson of Georgia | 160,215 | 47.17% | 0 | 0.00% | ||
| Constitutional Union | John Bell of Tennessee | Edward Everett of Massachusetts | 4,914 | 1.45% | 0 | 0.00% | ||
| Southern Democratic | John C. Breckinridge of Kentucky | Joseph Lane of Oregon | 2,331 | 0.69% | 0 | 0.00% | ||
| Liberty | Gerrit Smith of New York | Samuel McFarland of Pennsylvania | 35 | 0.01% | 0 | 0.00% | ||
| Total | 339,666 | 100.00% | 11 | 100.00% | ||||
See also
References
- ^ "US President - Liberty (Union) National Convention". Our Campaigns. November 24, 2008.
- ^ "RADICAL ABOLITION NATIONAL CONVENTION". Douglass' Monthly. October 1860. p. 352.
- ^ "1860 Presidential General Election Results - Illinois".
