1872 United States presidential election in Nebraska
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| Elections in Nebraska |
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 Government |
The 1872 United States presidential election in Nebraska took place on November 5, 1872, as part of the 1872 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.
Nebraska voted for the Republican candidate, Ulysses S. Grant, over Liberal Republican candidate Horace Greeley. Grant won Nebraska by a margin of 41.36%.
With 70.68% of the popular vote, Nebraska would be Grant's fourth strongest victory in terms of percentage in the popular vote after Vermont, South Carolina and Rhode Island.[1]
Results
| 1872 United States presidential election in Nebraska[2][3] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Republican | Ulysses S. Grant of Ohio | Henry Wilson of Massachusetts | 18,329 | 70.68% | 3 | 100.00% | ||
| Liberal Republican | Horace Greely of New York | Benjamin Gratz Brown of Missouri | 7,603 | 29.32% | 0 | 0.00% | ||
| Total | 25,932 | 100.00% | 3 | 100.00% | ||||
References
- ^ "1872 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
- ^ "1872 Presidential General Election Results - Nebraska". U.S. Election Atlas. Retrieved 3 December 2017.
- ^ "1872 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 3 December 2017.
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