Eleutheros Cooke House (410 Columbus Avenue, Sandusky, Ohio)

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Eleutheros Cooke House
Eleutheros Cooke House at 410 Columbus.jpg
Front of the house
Eleutheros Cooke House (410 Columbus Avenue, Sandusky, Ohio) is located in Ohio
Eleutheros Cooke House (410 Columbus Avenue, Sandusky, Ohio)
Eleutheros Cooke House (410 Columbus Avenue, Sandusky, Ohio) is located in the US
Eleutheros Cooke House (410 Columbus Avenue, Sandusky, Ohio)
Location 410 Columbus Ave., Sandusky, Ohio
Coordinates 41°27′12″N 82°42′36″W / 41.45333°N 82.71000°W / 41.45333; -82.71000Coordinates: 41°27′12″N 82°42′36″W / 41.45333°N 82.71000°W / 41.45333; -82.71000
Built 1827
Architectural style Greek Revival
MPS Sandusky MRA
NRHP reference # 82001390[1]
Added to NRHP October 20, 1982

The Eleutheros Cooke House at 410 Columbus Avenue in Sandusky, Ohio is the oldest surviving house in Sandusky. It is a Greek Revival style house that was built in 1827 by Eleutheros Cooke, one of the first settlers in the area and its first lawyer. The original front porch of the house saw General William Henry Harrison receive a flag from the women of Sandusky, in 1835.[2]

It was listed on the National Register of Historic Places in 1982.[1]

See also[edit]

References[edit]

  1. ^ a b National Park Service (2009-03-13). "National Register Information System". National Register of Historic Places. National Park Service. 
  2. ^ Lorrie K. Owen, ed. (1999). "Ohio Historic Places Dictionary, Volume 2". Somerset Publishers, Inc. p. 344.