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1836 United States presidential election in New Hampshire

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1836 United States presidential election in New Hampshire

← 1832 November 3 - December 7, 1836 1840 →
 
Nominee Martin Van Buren William Henry Harrison
Party Democratic Whig
Home state New York Ohio
Running mate Richard Mentor Johnson Francis Granger
Electoral vote 7 0
Popular vote 18,697 6,228
Percentage 75.01% 24.99%

County Results
Van Buren
  50-60%
  60-70%
  70-80%
  80-90%


President before election

Andrew Jackson
Democratic

Elected President

Martin Van Buren
Democratic

The 1836 United States presidential election in New Hampshire took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

New Hampshire voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won New Hampshire by a margin of 50.02%. As of 2020, this remains the strongest ever performance by any presidential candidate in New Hampshire since the creation of the modern Democratic party in 1828.

Results

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1836 United States presidential election in New Hampshire[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 18,697 75.01% 7 100.00%
Whig William Henry Harrison of Ohio Francis Granger of New York 6,228 24.99% 0 0.00%
Total 24,925 100.00% 7 100.00%

See also

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References

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  1. ^ "1836 Presidential General Election Results - New Hampshire". U.S. Election Atlas. Retrieved December 23, 2013.