1828 United States presidential election in Tennessee
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| Elections in Tennessee |
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 Government |
The 1828 United States presidential election in Tennessee took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose 11 representatives, or electors to the Electoral College, who voted for President and Vice President.
Tennessee voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Tennessee, his home state, by a wide margin of 90.38%.
Results
| United States presidential election in Tennessee, 1828[1] | |||||
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| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic | Andrew Jackson | 44,293 | 95.19% | 11 | |
| National Republican | John Quincy Adams | 2,240 | 4.81% | 0 | |
| Totals | 46,533 | 100.0% | 11 | ||
References
- ^ "1828 Presidential General Election Results - Tennessee". U.S. Election Atlas. Retrieved 28 February 2013.
State and district results of the 1828 United States presidential election | ||
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