1996 United States presidential election in Wyoming
 | |||||||||||||||||||||||||||||||||
| |||||||||||||||||||||||||||||||||
| |||||||||||||||||||||||||||||||||
 County Results
Clinton—40-50%
Dole—40-50%
Dole—50-60%
Dole—60-70% | |||||||||||||||||||||||||||||||||
| |||||||||||||||||||||||||||||||||
| Elections in Wyoming |
|---|
 |
The 1996 United States presidential election in Wyoming took place on November 5, 1996, as part of the 1996 United States presidential election. Voters chose 9 representatives, or electors to the Electoral College, who voted for president and vice president.
Wyoming was won by Senator Bob Dole (R-KS), with Dole winning 49.81% to 36.84% over President Bill Clinton (D) by a margin of 12.97%. Billionaire businessman Ross Perot (Reform Party of the United States of America-TX) finished in third, with 12.25% of the popular vote.[1] As of the 2016 presidential election[update], this is the last election in which Sweetwater County voted for the Democratic candidate.
With 12.25% of the popular vote, Wyoming would prove to be Ross Perot's fourth strongest state in the 1996 election after Maine, Montana and Idaho[2].
Results
| United States presidential election in Wyoming, 1996 | ||||||
|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Votes | Percentage | Electoral votes | |
| Republican | Bob Dole | Jack Kemp | 105,388 | 49.81% | 3 | |
| Democratic | Bill Clinton (incumbent) | Al Gore | 77,934 | 36.84% | 0 | |
| Reform | Ross Perot | Patrick Choate | 25,928 | 12.25% | 0 | |
| Libertarian | Harry Browne | Jo Jorgensen | 1,739 | 0.82% | 0 | |
| Natural Law | Dr. John Hagelin | Dr. V. Tompkins | 582 | 0.28% | 0 | |
References
- ^ http://uselectionatlas.org/RESULTS/index.html
- ^ "1996 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
