Talk:Positronium

Inconsistent Lifetimes

The lifetimes cited for para-positronium are inconsistent. The derived result is outside the bounds of the experimental result from 2007. As a more recent and experimental result should it perhaps be left in preference to the theoretical result in the case of positronium? — Preceding unsigned comment added by 24.9.63.178 (talk) 19:09, 4 March 2014 (UTC)

Reorder?

It would make more sense to me to place the di-positronium at the bottom, and the discovery/prediction above it. Any wanna do it?

LifeTimes

From my understanding, positronium can either exist in para- or ortho- states. (There is no way to add two spin-1/2 particles so you get total spin other than 0 or 1.) If the lifetime of the para state is 10^-10, and the lifetime of the ortho state is 10^-8, then how can the (presumably average) lifetime of positronium be 10^-7? What's going on here? Ckerr 08:24, 11 November 2005 (UTC)

Could be a difference in meaning of "lifetime" the 10^-7 number is "at most". — Omegatron 06:28, 11 November 2005 (UTC)

If so, that's an unusual use of the term "lifetime", since there is no such thing as a maximum lifetime. It's "possible" to have any compound, no matter how unstable, living for an arbitrary amount of time, since radioactive decay is a stochastic process. Ckerr 08:24, 11 November 2005 (UTC)

I've added a clarifying bit of material on the lifetimes of the two states of Ps. The mean lifetime is the amount of time it takes for the population of an exponentially decaying population to be reduced by a factor of "e" (=2.71828...). The mean lifetime is a bit longer than the half-life by about 30%.

Time calculations

From where the two formulas follow?--188.26.22.131 (talk) 15:56, 30 June 2011 (UTC)

practical uses?

I came here hoping to find some solution to the energy crisis. Someone should add to the article how this could be useful? 4.230.102.132 05:32, 24 November 2005 (UTC)

Positronium would not be a solution to the energy crisis in any useful way. Positronium does not store energy for any useful length of time (minutes to days), nor can it be stabilized to do so. No energy is gained in the process of positron annihilation, since it requires energy to create anti-matter in the first place. There is no such thing as a "positron well" where one can go get usefully large amounts of antimatter to be stored. In principle, one could store energy in positrons (or other antimatter) by creating the antimatter in the first place and storing it in charged particle traps, then releasing it in a controlled way to use the annihilation radiation as energy. But it's not a solution to the rising cost of oil.

At best, anti-matter is an interesting tool of science-fiction authors as an energy source. In reality (with present technology) it is very inefficient and actually wastes energy as a result of the equipment required (typically, powerful accelerators). Nimur 01:01, 3 April 2006 (UTC)

--Mplskid 07:30, 12 July 2006 (UTC)--Mplskid 07:30, 12 July 2006 (UTC)--Mplskid 07:30, 12 July 2006 (UTC)--Mplskid 07:30, 12 July 2006 (UTC)

Anything emitted during the "spiral"?

The particles "spiral" closer to each other (although this actually takes place in quantized steps of decreasing radius), until their existence is terminated by electron-positron annihilation. At annihilation, gamma rays are produced.

Is anything produced during the "spiral"? And if not, what happens to that energy? Ewlyahoocom 12:19, 1 April 2006 (UTC)

I'm not 100% sure, but I do not believe there is electromagnetic radiation during this inward spiral (this would be a classical phenomenon). Instead, the energy is converted between orbital and spin angular momentum, so the system is not losing (or radiating) energy. After the particles annihilate, then they produce the gamma radiation. Nimur 00:58, 3 April 2006 (UTC)

Hmm. I'm not so sure about this explanation. Positrons and electrons have spin 1/2, so exactly how could they get more spin angular momentum? They can't magically turn into bosons, which is why they're called spin 1/2 particles. A decreasing radius of orbit would necessitate a change in orbital angular momentum, so something must be going on. From my background (one postgraduate class in particle physics) I would say that EM radiation is emitted. This would explain why positronium annihilation has a well-defined energy: all the extra energy is bled off in the form of photons before the two antiparticles annihilate.

There is no "spiral." This is a classical notion, implying the existence of trajectories, which is inconsistent with the tenets of quantum mechanics. Any atom in its ground state exists as a cloud of charge distribution that is static in the absence of external forces. Any two particles within an atom can be found within a prescribed distance from each other with a definite probability that can be calculated. Positronium is a genuine atom, and its two particles must be within a certain small distance in order to annihilate. The probability for this is calculable, and represents the fraction of time the particles are able to annihilate, which leads to the annihilation rate or lifetime.Mplskid 07:30, 12 July 2006 (UTC)

Ewlyahoocom asked the right question. Spiral is correct, only QM does not describe it. Also, it is probably not monotonic - and definitely not in quantized steps. Radiation is correct, only it is not far-field (propagating) radiation. The energy goes into kinetic energy and field energy. Since positronium does not have enough angular momentum to form a photon (needed for a quantized step), it cannot radiate far-field. If the conditions were right, it could radiate photon pairs prior to annihilation. However, until annihilation actually begins, the field-energy and photon-frequency relations are not correct. I'm trying to figure out the mechanics of the annihilation process right now. (That requires understanding what an electron really is - and not its average, or statistical, QM picture.)

Congratulations. I'm glad to see someone else who is looking beyond equations and seeking mechanisms. I've never seen anyone else recognize the requirement for sufficient angular momentum to radiate photons. (I believe that HEL's comments below are incorrect because higher-order transitions require even more Ang. Mom. - There is a reason why 0=>0 transitions are highly forbidden.) Two suggestions/questions:

       1. If electrons and positrons are completely EM energy, then as they approach one another, the far-fields cancel 
          and the near-fields (in between) grow. Thus, charge far-field is converted into KE, & mass is converted into 
          near-field energy. Since energy is proportional to field squared, the "mass" of the e-p pair moves toward the 
          center point. Does this allow the KE & PE to balance so that the spiral (from atomic-orbit size to annihilation) 
          can occur w/o radiation (until the final gammas form)?  Does the problem require relativistic treatment? 
          At annihilation, but prior to gamma emission, all of the e-p mass has been converted into field energy (centered, 
          but distributed?). 
       2. Does the fact that the e-p pair is a boson allow the Klein-Gordan solution of a deep energy state (E = ~ mc^2 
          for n=0, or the nought orbit - my nomenclature) to be a metastable state just prior to annihilation? [see J. Naudts, 
          “On the Hydrino State of the Relativistic Hydrogen Atom,” http://arxiv.org/abs/physics/0507193 ]  
     Perhaps you've already addressed these points and figured everything out.    - - Aqm2241 (talk) 18:08, 17 January 2010 (UTC)

The "spiral" is a classical approximation to the stepping-down of the quantized energy levels. It is a valid approximation for highly excited states of positronium, just like it is for ordinary atoms such as hydrogen. Transitions of the positronium atom downward to lower energy levels emit photons carrying energy corresponding to the energy difference between the levels (energy is conserved). The angular momentum argument is bogus; just like for atoms, you can always get transitions at some level even if they're not electric dipole transitions. The annihilation process is well understood in quantum electrodynamics -- it's just $e^{+}e^{-}\to \gamma \gamma$ through a t-channel electron. The annihilation tends to happen at the end of the "spiral-down" process because it depends on there being a wavefunction overlap between the electron and the positron, which is suppressed for states with large orbital angular momentum. HEL 22:15, 2 February 2007 (UTC)

-To anwser the first question asked why is the mean life time 10^-7 s. The 2 forms of positronium are not produced in equal quanties when its formed. para-Ps can only be formed in one quantum state where the spins are anti-parallel (↑↓-↓↑)/sqrt(2) S=0. and ortho-Ps can be formed in one of three quantum states where the spins are parallel ↑↑, ↓↓, or (↑↓+↓↑)/sqrt(2) S=1. If you add (1/4)*0.125 ns + (3/4)*143 ns = 1.07*10^-7 s

Somewhat pertinent may be a Sci.Scoop.com Article, called, "Negatron plus Positron equals Zerotron?" which suggests that annililation occurs on a specific orientation of the electron and positron and that annihilation and pair-production are complementary processes involving a previously unsuspected symmetrical oscillator having the same mass as either of the "half-oscillators," the electron and positron. This may be erroneous conjencture, or a new and valid viewpoint on annihilation/pair-production.64.68.162.60 (talk) 18:16, 31 August 2010 (UTC)

prediction in 1932 or 1934?

The obit for Martin Deutsch, as well as his wiki page, says its properties were predicted in 1932 by C.D. Anderson of Caltech. This page says it was predicted by Stjepan Mohorovičić in 1934. Which is correct? --24.147.86.187 23:51, 3 October 2007 (UTC)

— Probably both. That happens a lot with physics, since 99% of the required work will have been done by someone else just before 1932. Anaholic 15:30, 17 October 2007 (UTC)

Referring to triplet state as parallel spins is misleading

The singlet state is a superposition of the two antiparallel spins and is antisymmetric as mentioned in the comment above, and two of the triplet have parallel spins, but one of the three has symmetric antiparallel spins, as also stated in the comment above. I think this should be made clearer, probably by just writing out the spin states or linking to a page where this is done. What do people think? —Preceding unsigned comment added by 84.59.185.159 (talk) 17:46, 2 July 2008 (UTC)

Spectroscopic nomenclature of ortho-positronium

Shouldn't it be n=1 2S+1=3 L=0 J=L+S=|L-S|=1 ? —Preceding unsigned comment added by 92.75.220.9 (talk) 23:41, 14 November 2008 (UTC)

Optical spectrum

What are the wavelengths of the EMR emitted during state transitions (i.e. the emission spectrum of postronium)? Has that radiation been experimentally? --Jorge Stolfi (talk) 18:59, 9 August 2009 (UTC)

Double the wavelength of Hydrogen and yes they have been observed. 128.40.2.153 (talk) 15:51, 11 March 2010 (UTC)

Anti-hydrogen

Shouldn't this article also talk about the similarity to anti-hydrogen? If conceptually think of the electron as the pseudo-nucleus, then it looks like anti-hydrogen. 65.93.12.101 (talk) 12:05, 24 March 2011 (UTC)

Same symbol as Praseodymium?

If my memory serves me well, Ps is the symbol for Praseodymium.... And Positronium? For a lack of better words, what's up with that? Cossacksson (talk) 03:56, 21 December 2012 (UTC)

Apparently it's Pr, as a moment's effort reveals. —Tamfang (talk) 06:08, 19 February 2013 (UTC)

Well, to make it clearer, praseodymium is Pr, while positronium is Ps. Protonium is Pn, though that could also mean a generic pnictogen (P, As, Sb, or Bi). Double sharp (talk) 08:17, 11 January 2016 (UTC)

Lifetime Puzzle - History and Resulution

For a while there was an issue of the experimental lifetime disagreeing with theory that was resolved in 2003. How much should be discussed? The 'Prediction and Discovery' section could be changed to a 'History' section.

http://physicsworld.com/cws/article/news/2003/may/28/positronium-puzzle-is-solved — Preceding unsigned comment added by Timetraveler3.14 (talk • contribs) 20:37, 9 December 2014 (UTC)

It was apparently resolved in 2003 by a group at U Michigan (Phys.Rev.Lett. 90 (2003) 203402). However, a short article in Progress in Physics in 2007, Twenty-year anniversary of the orthopositronium lifetime anomalies: the puzzle remains unresolved.(A Letter by the Editor-in-Chief): An article from: Progress in Physics indicates the Michigan experiment didn’t actually resolve the problem! So my question is: was this discrepancy resolved once and for all?TonyMath (talk) 08:12, 22 May 2015 (UTC)

I checked. The O-Ps lifetime puzzle seems to have been resolved. The latest experiments seem to be conclusive as they can differentiate between the $O(\alpha )$ and $O(\alpha ^{2})$ corrections to the lowest order decay rate. Some references are Y. Kataoka, S. Asai, and T. Kobayashi, Phys. Lett. B 671, 219 (2009) [preprint arXiv report 0809.1594v1 [hep-ex]] and T. Namba, Progress of Theoretical and Experimental Physics 04D003 (2012).This wikipedia site needs to be updated accordingly though.TonyMath (talk) 00:31, 25 May 2015 (UTC)

I added some text, but I see that figures for this ortho-Ps lifetime in the Wikipedia article are quite inconsistent. Graeme Bartlett (talk) 13:07, 26 May 2015 (UTC)

== Inconsistent units for lifetimes.

There are references to 1.244 \times 10^{-10}s, 142.05±0.02 ns, and 1.386 \times 10^{-7}s. This would be much easier to read if it was all in ns: 0.1244 ns, 142.02±0.02 ns, and 138.6 ns. (In particular, it makes it much easier for a reader to compare the lifetime of para- and ortho- forms. 62.2.246.66 (talk) 15:58, 27 March 2017 (UTC)