1836 United States presidential election in Missouri
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Elections in Missouri |
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The 1836 United States presidential election in Missouri took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
Missouri voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White. Van Buren won Missouri by a margin of 19.96%.
Results
United States presidential election in Missouri, 1836[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Martin Van Buren | 10,995 | 59.98% | 4 | |
Whig | Hugh White | 7,337 | 40.02% | 0 | |
Totals | 18,332 | 100.0% | 4 |
References
- ^ "1836 Presidential General Election Results - Missouri". U.S. Election Atlas. Retrieved 15 April 2013.