1844 United States presidential election in Georgia
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| Elections in Georgia |
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The 1844 United States presidential election in Georgia took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose 10 representatives, or electors to the Electoral College, who voted for President and Vice President.
Georgia voted for the Democratic candidate, James K. Polk, over Whig candidate Henry Clay. Polk won Georgia by a margin of 2.38%.
Results
| United States presidential election in Georgia, 1844[1] | ||||||||
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| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | James K. Polk of Tennessee | George M. Dallas of Pennsylvania | 44,147 | 51.19% | 10 | 100.00% | ||
| Whig | Henry Clay of Kentucky | Theodore Frelinghuysen of New York | 42,100 | 48.81% | 0 | 0.00% | ||
| Total | 86,247 | 100.00% | 10 | 100.00% | ||||
References
- ^ "1844 Presidential General Election Results - Georgia". U.S. Election Atlas. Retrieved 23 December 2013.
State and district results of the 1844 United States presidential election | ||
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