Chapeshlu

From Wikipedia, the free encyclopedia
Jump to: navigation, search
For the administrative subdivision, see Chapeshlu District.
Chapeshlu
چاپشلو
city
Chapeshlu is located in Iran
Chapeshlu
Chapeshlu
Coordinates: 37°21′06″N 59°04′36″E / 37.35167°N 59.07667°E / 37.35167; 59.07667Coordinates: 37°21′06″N 59°04′36″E / 37.35167°N 59.07667°E / 37.35167; 59.07667
Country  Iran
Province Razavi Khorasan
County Dargaz
Bakhsh Chapeshlu
Population (2006)
 • Total 2,247
Time zone IRST (UTC+3:30)
 • Summer (DST) IRDT (UTC+4:30)
Chapeshlu at GEOnet Names Server

Chapeshlu (Persian: چاپشلو‎‎, also Romanized as Chāpeshlū and Chāpishlu; formerly, Chāvosh and Chowveshlī)[1] is a city in and the capital of Chapeshlu District, in Dargaz County, Razavi Khorasan Province, Iran. At the 2006 census, its population was 2,247, in 616 families.[2]

References[edit]

  1. ^ Chapeshlu can be found at GEOnet Names Server, at this link, by opening the Advanced Search box, entering "-3058069" in the "Unique Feature Id" form, and clicking on "Search Database".
  2. ^ "Census of the Islamic Republic of Iran, 1385 (2006)". Islamic Republic of Iran. Archived from the original (Excel) on 2011-11-11.