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Humboldt Township, Humboldt County, Iowa

Coordinates: 42°51′40″N 91°09′14″W / 42.86111°N 91.15389°W / 42.86111; -91.15389
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Humboldt Township
Township
Location in Humboldt County
Location in Humboldt County
Coordinates: 42°51′40″N 91°09′14″W / 42.86111°N 91.15389°W / 42.86111; -91.15389
Country United States
State Iowa
CountyHumboldt
Established1857
Area
 • Total
36.6 sq mi (95 km2)
 • Land36.6 sq mi (95 km2)
 • Water0.0 sq mi (0 km2)
Elevation
915 ft (279 m)
Population
 (2000)
 • Total
624
 • Density17/sq mi (7/km2)
Time zoneUTC-6 (CST)
 • Summer (DST)UTC-5 (CDT)
ZIP codes
50558 (Livermore)
50560 (Lu Verne)
GNIS feature ID0468060

Humboldt Township is one of twelve townships in Humboldt County, Iowa, USA.[1] As of the 2000 census, its population was 624. Despite its name, the township does not contain the City of Humboldt.

Geography

According to the United States Census Bureau, Humboldt Township covers an area of 36.6 square miles (95 km2); all of this is land.

Cities, towns, villages

Adjacent townships

Cemetery

The township contains Mount Calvary Cemetery.[1]

Political districts

References

  1. ^ a b "Humboldt township, Humboldt County, Iowa (IA)". U.S. Census Bureau. Breakdown. Retrieved January 21, 2010.
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