Palladium tetrafluoride
(Redirected from Palladium(IV) fluoride)
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3D model (JSmol)
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PubChem CID
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| Properties | |
| F4Pd | |
| Molar mass | 182.41 g·mol−1 |
| Appearance | pink[1] or brick-red[2] crystalline solid |
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Other cations
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Platinum(IV) fluoride |
Related compounds
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Palladium(II) fluoride Palladium(II,IV) fluoride |
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).
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Palladium (IV) fluoride, also known as palladium tetrafluoride, is the chemical compound of palladium and fluorine with the chemical formula PdF4. The palladium atoms in PdF4 are in the +4 oxidation state.[2][3]
Synthesis
[edit]Palladium tetrafluoride has been prepared by reacting palladium(II,IV) fluoride with fluorine gas at pressures around 7 atm and at 300 °C for several days.[1]
Reactivity
[edit]PdF4 is a strong oxidising agent and undergoes rapid hydrolysis in moist air.[1]
See also
[edit]References
[edit]- ^ a b c Rao, P. R.; Tressaud, A.; Bartlett, N. (1976). "The tetrafluorides of iridium, rhodium and palladium". J. Inorg. Nucl. Chem. 28: 23–28. doi:10.1016/0022-1902(76)80588-X.
- ^ a b Greenwood, Norman N.; Earnshaw, Alan (1997). Chemistry of the Elements (2nd ed.). Butterworth-Heinemann. pp. 1152–1153. ISBN 978-0-08-037941-8.
- ^ Housecroft, C. E.; Sharpe, A. G. (2008). Inorganic Chemistry (3rd ed.). Prentice Hall. pp. 788–789. ISBN 978-0-13-175553-6.