1852 United States presidential election in Georgia
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| Elections in Georgia |
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The 1852 United States presidential election in Georgia took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose ten representatives, or electors to the Electoral College, who voted for President and Vice President.
Georgia voted for the Democratic candidate, Franklin Pierce, over Whig candidates Winfield Scott and Daniel Webster. Daniel Webster was not chosen as the Whig Party candidate, but was placed on the ballot without permission by a group of former Whigs, now Know Nothings.[1] Pierce won Georgia by a margin of 38.10%.
Results
| United States presidential election in Georgia, 1852[2][3] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Franklin Pierce of New Hampshire | William R. King of Alabama | 40,516 | 64.70% | 10 | 100.00% | ||
| Whig | Winfield Scott of New Jersey | William A. Graham of North Carolina | 16,660 | 26.60% | 0 | 0.00% | ||
| Whig | Daniel Webster of Massachusetts | N/A of N/A | 5,324 | 8.50% | 0 | 0.00% | ||
| Southern Rights | George M. Troup | N/A | 126 | 0.20% | 0 | 0.00% | ||
| Total | 62,626 | 100.00% | 10 | 100.00% | ||||
References
- ^ Ogg, Frederic Austin (1914). Daniel Webster. p. 407.
- ^ "1852 Presidential General Election Results - Georgia". U.S. Election Atlas. Retrieved 2 December 2017.
- ^ "1852 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 2 December 2017.
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