United States presidential election in Georgia, 1828

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United States presidential election in Georgia, 1828
Georgia (U.S. state)
1824 ←
October 31 – December 2, 1828 → 1832

  Andrew Jackson.jpg JohnQAdams.png
Nominee Andrew Jackson John Quincy Adams
Party Democratic National Republican
Home state Tennessee Massachusetts
Running mate John C. Calhoun Richard Rush
Electoral vote 9 0
Popular vote 19,362 642
Percentage 96.79% 3.21%

The 1828 United States presidential election in Alabama took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.

Georgia voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Georgia by a margin of 93.58%.

Results[edit]

United States presidential election in Georgia, 1828[1]
Party Candidate Votes Percentage Electoral votes
Democratic Andrew Jackson 19,362 96.79% 9
National Republican John Quincy Adams 642 3.21% 0
Totals 20,004 100.0% 9

References[edit]

  1. ^ "1828 Presidential General Election Results - Georgia". U.S. Election Atlas. Retrieved 28 February 2013.