1992 United States presidential election in Montana

Main article: United States presidential election, 1992

United States presidential election in Montana, 1992

November 3, 1992

Nominee Bill Clinton George H. W. Bush Ross Perot Party Democratic Republican Independent Home state Arkansas Texas Texas Running mate Al Gore Dan Quayle James Stockdale Electoral vote 3 0 0 Popular vote 154,507 144,207 107,225 Percentage 37.6% 35.1% 26.1%

President before election George H. W. Bush Republican Elected President Bill Clinton Democratic

The 1992 United States presidential election in Montana took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

Montana had two seats in the House of Representatives in 1988, it lost one seat in 1992. Therefore, there was only one seat in 1992, and the seat hasn't returned since (it might return in 2024 according to the very high population for its number of seats). This was also the only time since 1964 when Montana voted Democratic.

Montana was won by Governor Bill Clinton (D-Arkansas) with 37.63% of the popular vote over incumbent President George H. W. Bush (R-Texas) with 35.12%. Businessman Ross Perot (I-Texas) finished in third with 26.12% of the popular vote. Clinton ultimately won the national vote, defeating incumbent President Bush. It was the first time the state voted for a Democrat since it was won by President Lyndon B. Johnson in 1964.

Results

United States presidential election in Montana, 1992
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Bill Clinton	154,507	37.63%	3
	Republican	George H.W. Bush (incumbent)	144,207	35.12%	0
	Independent	Ross Perot	107,225	26.12%	0
	America First	James "Bo" Gritz	3,658	0.89%	0
	Libertarian	Andre Marrou	986	0.24%	0
Totals			410,583	100.0%	3