1918 Major League Baseball season
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|1918 MLB season|
|League||Major League Baseball|
|Duration||April 15 – September 11, 1918|
|AL champions||Boston Red Sox|
|AL runners-up||Cleveland Indians|
|NL champions||Chicago Cubs|
|NL runners-up||New York Giants|
|Champions||Boston Red Sox|
Major league baseball final standings
American League final standings
|Boston Red Sox||75||51||0.595||—||49–21||26–30|
|New York Yankees||60||63||0.488||13½||37–29||23–34|
|St. Louis Browns||58||64||0.475||15||23–30||35–34|
|Chicago White Sox||57||67||0.460||17||30–26||27–41|
National League final standings
|New York Giants||71||53||0.573||10½||35–21||36–32|
|St. Louis Cardinals||51||78||0.395||33||32–40||19–38|
The Red Sox defeated the Cubs, four games to two.
- September 2 - In the last game of the season, against the Chicago White Sox, Detroit Tigers centrefielder Ty Cobb fields at third base and also pitches, yielding three hits and one run in two innings.
- Paschal, John. "Once Upon A Time: When Hall of Famers Go One-And-Done". tht.fangraphs.com. Retrieved April 2, 2019.
- 1918 Major League Baseball season schedule at Baseball Reference Fetched January 14, 2018
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