1836 United States presidential election in Georgia
.svg){kind=small} | ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
| Elections in Georgia |
|---|
 |
The 1836 United States presidential election in Georgia took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 11 representatives, or electors to the Electoral College, who voted for president and vice president.
Georgia voted for Whig candidate Hugh White over the Democratic candidate, Martin Van Buren. White won Georgia by a margin of 3.6%.
Results
| United States presidential election in Georgia, 1836[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Whig | Hugh White | 24,481 | 51.80% | 11 | |
| Democratic | Martin Van Buren | 22,778 | 48.20% | 0 | |
| Totals | 47,259 | 100.0% | 11 | ||
References
- ^ "1836 Presidential General Election Results - Georgia". U.S. Election Atlas. Retrieved 4 August 2012.
State and district results of the 1836 United States presidential election | ||
|---|---|---|
 | ||
  | This Georgia elections-related article is a stub. You can help Wikipedia by expanding it. |