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1900 United States presidential election in Kansas

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1900 United States presidential election in Kansas

← 1896 November 6, 1900 1904 →
 
Nominee William McKinley William J. Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate Theodore Roosevelt Adlai Stevenson I
Electoral vote 10 0
Popular vote 185,955 162,601
Percentage 52.56% 45.96%

President before election

William McKinley
Republican

Elected President

William McKinley
Republican

The 1900 United States presidential election in Kansas took place on November 6, 1900. All contemporary 45 states were part of the 1900 United States presidential election. Kansas voters chose ten electors to the Electoral College, which selected the president and vice president.

Kansas was won by the Republican nominees, incumbent President William McKinley of Ohio and his running mate Theodore Roosevelt of New York. McKinley won the state by a margin of 6.60 percentage points. McKinley had previously lost the state to Democrat William Jennings Bryan four years earlier while Bryan would later lose the state again to another Republican (William Howard Taft) in 1908.

Results

1900 United States presidential election in Kansas[1]
Party Candidate Votes Percentage Electoral votes
Republican William McKinley 185,955 52.56% 10
Democratic William Jennings Bryan 162,601 45.96% 0
Prohibition John Woolley 3,605 1.02% 0
Social Democratic Eugene Debs 1,605 0.45% 0
Totals 353,766 100.00% 10
Voter turnout

References

  1. ^ Dave Leip's U.S. Election Atlas; Presidential General Election Results – Kansas

Notes