1880 United States presidential election in Minnesota
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| Elections in Minnesota |
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The 1880 United States presidential election in Minnesota took place on November 2, 1880, as part of the 1880 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.
Minnesota voted for the Republican nominee, James A. Garfield, over the Democratic nominee, Winfield Scott Hancock. Garfield won the state by a margin of 30.25%.
With 62.28% of the popular vote, Minnesota would be Garfield's third strongest victory in terms of percentage in the popular vote after Vermont and Nebraska.[1]
Results
| 1880 United States presidential election in Minnesota[2] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Republican | James Abram Garfield of Ohio | Chester Alan Arthur of New York | 93,902 | 62.87% | 3 | 100.00% | ||
| Democratic | Winfield Scott Hancock of Pennsylvania | William Hayden English of Indiana | 53,315 | 35.36% | 0 | 0.00% | ||
| Greenback | James Baird Weaver of Iowa | Barzillai Jefferson Chambers of Texas | 3,267 | 2.17% | 0 | 0.00% | ||
| Prohibition | Neal Dow of Maine | Henry Adams Thompson of Ohio | 286 | 0.19% | 0 | 0.00% | ||
| Total | 150,770 | 100.00% | 5 | 100.00% | ||||
References
- ^ "1880 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
- ^ "1880 Presidential General Election Results - Minnesota".
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