1944 United States presidential election in Delaware
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All 3 Delaware votes to the Electoral College | ||||||||||||||||||||||||||
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 County Results
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| Elections in Delaware |
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The 1944 United States presidential election in Delaware took place on November 7, 1944, as part of the 1944 United States presidential election. Delaware voters chose 3[2] representatives, or electors, to the Electoral College, who voted for president and vice president.
Delaware was won by incumbent President Franklin D. Roosevelt (D–New York), running with Senator Harry S. Truman, with 54.38% of the popular vote, against Governor Thomas E. Dewey (R–New York), running with Governor John W. Bricker, with 45.27% of the popular vote.[3][4]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | Franklin D. Roosevelt (inc.) | 68,166 | 54.38% | |
| Republican | Thomas E. Dewey | 56,747 | 45.27% | |
| Write-in | 448 | 0.36% | ||
| Total votes | 125,361 | 100.00% | ||
References
- ^ "United States Presidential election of 1944 - Encyclopædia Britannica". Retrieved December 26, 2017.
- ^ "1944 Election for the Fortieth Term (1945-49)". Retrieved December 26, 2017.
- ^ "1944 Presidential General Election Results - Delaware". Retrieved December 26, 2017.
- ^ "The American Presidency Project - Election of 1944". Retrieved December 26, 2017.
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