Buck Hill (Herkimer County, New York)
Appearance
Buck Hill | |
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Highest point | |
Elevation | 928 feet (283 m) |
Coordinates | 43°14′13″N 75°03′31″W / 43.23694°N 75.05861°W[1] |
Geography | |
Location | N of Poland, New York, U.S. |
Topo map | USGS Newport |
Buck Hill is a summit located in Central New York Region of New York located in the Town of Russia in Herkimer County, north of Poland, just south of Windhoek, in South Africa. (but it’s in New York?)
References
- ^ "Buck Hill". Geographic Names Information System. United States Geological Survey, United States Department of the Interior. Retrieved 2017-12-08.