Săcălaz

Coordinates: 45°45′N 21°07′E / 45.750°N 21.117°E / 45.750; 21.117
From Wikipedia, the free encyclopedia

This is an old revision of this page, as edited by Kelutral (talk | contribs) at 10:45, 6 June 2018. The present address (URL) is a permanent link to this revision, which may differ significantly from the current revision.

Săcălaz
Commune
Săcălaz is located in Romania
Săcălaz
Săcălaz
Coordinates: 45°45′N 21°7′E / 45.750°N 21.117°E / 45.750; 21.117
Country Romania
CountyTemplate:RO-TM
Government
 • MayorIlie Todașcă (PSD)
Area
119.49 km2 (46.14 sq mi)
Population
 (2002)[1]
6,273
Time zoneUTC+2 (EET)
 • Summer (DST)UTC+3 (EEST)

Săcălaz is a commune in Timiș County, Romania. It is composed of three villages: Beregsău Mare, Beregsău Mic and Săcălaz.

In Romanian In German In Hungarian In Serbian
Beregsău Mare Grossberegsau Berekszó Велики Берексов
Beregsău Mic Berekszónémeti Немет
Săcălaz Sackelhausen Szakálháza Секелаз

45°45′N 21°07′E / 45.750°N 21.117°E / 45.750; 21.117

References

  1. ^ Romanian census data, 2002; retrieved on March 1, 2010
Stub icon

This Timiș County location article is a stub. You can help Wikipedia by expanding it.

Retrieved from "https://en.wikipedia.org/w/index.php?title=Săcălaz&oldid=844672624"