1810 United States elections
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Incumbent president | James Madison (Democratic-Republican) |
---|---|
Next Congress | 12th |
Senate elections | |
Overall control | Democratic-Republican hold |
Seats contested | 11 of 34 seats[1] |
Net seat change | Federalist -1[2] |
House elections | |
Overall control | Democratic-Republican hold |
Seats contested | All 143 voting seats |
Net seat change | Democratic-Republican +13[2] |
The 1810 United States elections occurred in the middle of Democratic-Republican President James Madison's first term, during the First Party System. Members of the 12th United States Congress were chosen in this election. During the 12th Congress, Louisiana joined the union. Democratic-Republicans continued to control both chambers of Congress.
In the House, Democratic-Republicans picked up a moderate number of seats, increasing their already-dominant majority.[3]
In the Senate, Democratic-Republicans won a small number of seats, increasing their commanding majority.[4]
See also
[edit]References
[edit]- ^ Not counting special elections.
- ^ a b Congressional seat gain figures only reflect the results of the regularly-scheduled elections, and do not take special elections into account.
- ^ "Party Divisions of the House of Representatives". United States House of Representatives. Retrieved 25 June 2014.
- ^ "Party Division in the Senate, 1789-Present". United States Senate. Retrieved 25 June 2014.