1936 United States presidential election in Delaware
Appearance
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Elections in Delaware |
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The 1936 United States presidential election in Delaware was held on November 3, 1936. The state voters chose three electors to the Electoral College, who voted for president and vice president.
Delaware voted for Democratic Party candidate and incumbent President Franklin D. Roosevelt, who defeated Republican nominee, Kansas Governor Alf Landon. Roosevelt won the state by a margin of 9.77 percent.
While Landon lost the state, the 44.85% of the popular vote made Delaware his fifth strongest state in the 1936 election in terms of popular vote percentage after Vermont, Maine, New Hampshire and Kansas[1].
Results
United States presidential election in Delaware, 1936[2] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | Franklin Delano Roosevelt of New York | John Nance Garner of Texas | 69,702 | 54.62% | 3 | 100.00% | ||
Republican | Alf Landon of Kansas | Frank Knox of Texas | 57,236 | 44.85% | 0 | 0.00% | ||
Union | William Lemke of North Dakota | Thomas C. O'Brien of Massachusetts | 442 | 0.35% | 0 | 0.00% | ||
Socialist | Norman Thomas of New York | George A. Nelson of Wisconsin | 172 | 0.13% | 0 | 0.00% | ||
Communist | Earl Russell Browder of Kansas | James W. Ford of New York | 51 | 0.04% | 0 | 0.00% | ||
Total | 127,603 | 100.00% | 3 | 100.00% |
References
- ^ "1936 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
- ^ "1936 Presidential General Election Results - Delaware". U.S. Election Atlas. Retrieved 23 December 2013.