1996 United States presidential election in Montana
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| Elections in Montana |
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The 1996 United States presidential election in Montana took place on November 5, 1996. Voters chose 3 representatives, or electors to the Electoral College, who voted for President and Vice President.
Montana voted for Senate Majority Leader Bob Dole over President Bill Clinton by a slim margin of 2.88%.[1] Billionaire businessman Ross Perot (Reform Party of the United States of America-TX) finished in third with 13.56% of the popular vote in Montana.[2]
Results
| United States presidential election in Montana, 1996[3] | ||||||
|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Votes | Percentage | Electoral votes | |
| Republican | Bob Dole | Jack Kemp | 179,652 | 44.11% | 3 | |
| Democratic | Bill Clinton | Al Gore | 167,922 | 41.23% | 0 | |
| Reform | Ross Perot | Patrick Choate | 55,229 | 13.56% | 0 | |
| Libertarian | Harry Browne | Jo Jorgensen | 2,526 | 0.62% | 0 | |
| Natural Law (write in) | John Hagelin | Mike Tompkins | 1,754 | 0.43% | 0 | |
| Constitutional (write in) | Howard Phillips | Herbert Titus | 152 | 0.04% | 0 | |
| (write in) | Charles E. Collins | Rosemary Giumarra | 20 | 0.00% | 0 | |
| Independent (write in) | Write-ins | 5 | 0.00 | 0 | ||
| Socialist (write in) | Mary Cal Hollis | Eric Chester | 1 | 0.00 | 0 | |
