1836 United States presidential election in Ohio

Main article: United States presidential election, 1836

United States presidential election in Ohio, 1836

November 3 – December 7, 1836

File:WHenryHarrison.png Nominee William Henry Harrison Martin Van Buren Party Whig Democratic Home state Ohio New York Running mate Francis Granger Richard Johnson Electoral vote 21 0 Popular vote 104,958 96,238 Percentage 51.87% 47.56%

President before election Andrew Jackson Democratic Elected President Martin Van Buren Democratic

The 1836 United States presidential election in Ohio took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose twenty-one representatives, or electors to the Electoral College, who voted for President and Vice President.

Ohio voted for Whig candidate William Henry Harrison over Democratic candidate Martin Van Buren. Harrison won Ohio by a margin of 4.31%.

Results

United States presidential election in Ohio, 1836
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Whig	William Henry Harrison of Ohio	Francis Granger of New York	104,958	51.87%	21	100.00%
	Democratic	Martin Van Buren of New York	Richard M. Johnson of Kentucky	96,238	47.56%	0	0.00%
	N/A	Others	Others	1,137	0.56%	0	0.00%
Total				202,333	100.00%	21	100.00%