1936 United States presidential election in Rhode Island
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| Elections in Rhode Island |
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The 1936 United States presidential election in Rhode Island was held on November 3, 1936. The state voters chose four electors to the Electoral College, who voted for president and vice president.
Rhode Island voted for Democratic Party candidate and incumbent President Franklin D. Roosevelt, who won the state by a margin of 12.92 percent.
Results
| United States presidential election in Rhode Island, 1936[1] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Franklin Delano Roosevelt of New York | John Nance Garner of Texas | 165,238 | 53.10% | 4 | 100.00% | ||
| Republican | Alf Landon of Kansas | Frank Knox of Texas | 125,031 | 40.18% | 0 | 0.00% | ||
| Union | William Lemke of North Dakota | Thomas C. O'Brien of Massachusetts | 19,569 | 6.29% | 0 | 0.00% | ||
| Socialist Labor | John W. Aiken of Connecticut | Emil F. Teichert of New York | 929 | 0.30% | 0 | 0.00% | ||
| Communist | Earl Russell Browder of Kansas | James W. Ford of New York | 411 | 0.13% | 0 | 0.00% | ||
| Total | 311,178 | 100.00% | 4 | 100.00% | ||||
References
- ^ "1936 Presidential General Election Results - Rhode Island". U.S. Election Atlas. Retrieved 23 December 2013.
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