1940 United States presidential election in Kentucky
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All 11 Kentucky votes to the Electoral College | ||||||||||||||||||||||||||
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| Elections in Kentucky |
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The 1940 United States presidential election in Kentucky took place on November 5, 1940, as part of the 1940 United States presidential election. Kentucky voters chose eleven[2] representatives, or electors, to the Electoral College, who voted for president and vice president.
Kentucky was won by incumbent President Franklin D. Roosevelt (D–New York), running with Secretary of Agriculture Henry A. Wallace, with 57.45% of the popular vote, against Wendell Willkie (R–Indiana), running with Minority Leader Charles L. McNary, with 42.30% of the popular vote.[3][4]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | Franklin D. Roosevelt (inc.) | 557,322 | 57.45% | |
| Republican | Wendell Willkie | 410,384 | 42.30% | |
| Write-in | 2,457 | 0.25% | ||
| Total votes | 970,163 | 100% | ||
References
- ^ "United States Presidential election of 1940 - Encyclopædia Britannica". Retrieved August 20, 2018.
- ^ "1940 Election for the Thirty-ninth Term (1941-45)". Retrieved August 20, 2018.
- ^ "1940 Presidential General Election Results - Kentucky". Retrieved August 20, 2018.
- ^ "The American Presidency Project - Election of 1940". Retrieved August 20, 2018.
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