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1992 United States presidential election in North Carolina

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United States presidential election in North Carolina, 1992

← 1988 November 3, 1992 1996 →
 
Nominee George H. W. Bush Bill Clinton Ross Perot
Party Republican Democratic Independent
Home state Texas Arkansas Texas
Running mate Dan Quayle Al Gore James Stockdale
Electoral vote 14 0 0
Popular vote 1,134,661 1,114,042 357,864
Percentage 43.4% 42.7% 13.7%

County Results
  Clinton—60-70%
  Clinton—50-60%
  Clinton—40-50%
  Bush—40-50%
  Bush—50-60%
  Bush—60-70%

President before election

George H. W. Bush
Republican

Elected President

Bill Clinton
Democratic

The 1992 United States presidential election in North Carolina took place on November 3, 1992 throughout all 50 states and D.C., which was part of the 1992 United States presidential election. Voters chose 9 representatives, or electors to the Electoral College, who voted for President and Vice President.

North Carolina was very narrowly won by incumbent Republican President George H. W. Bush of Texas over his Democratic challenger, Governor Bill Clinton of Arkansas. Bush took 43.44% of the vote to Clinton's 42.65%, a margin of 0.79%.[1]

Billionaire businessman Ross Perot, running as an Independent, finished in third with 13.70% of the vote, a relatively strong showing for a third party candidate, and his second highest showing in the Southeast, behind only Florida.

Results

United States presidential election in North Carolina, 1992[2]
Party Candidate Votes Percentage Electoral votes
Republican George H. W. Bush (incumbent) 1,134,661 43.44% 14
Democratic Bill Clinton 1,114,042 42.65% 0
Independent Ross Perot 357,864 13.70% 0
Libertarian Andre Marrou 5,171 0.20% 0
New Alliance Party Lenora Fulani (write-in) 59 0.00% 0
Natural Law Dr. John Hagelin (write-in) 41 0.00% 0
Socialist Workers Party James Warren (write-in) 12 0.00% 0
Totals 2,611,850 100.0% 14
Voter turnout 54.52%

References