1940 United States presidential election in Missouri
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All 15 Missouri votes to the Electoral College | ||||||||||||||||||||||||||
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| Elections in Missouri |
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The 1940 United States presidential election in Missouri took place on November 5, 1940, as part of the 1940 United States presidential election. Missouri voters chose fifteen[2] representatives, or electors, to the Electoral College, who voted for president and vice president.
Missouri was won by incumbent President Franklin D. Roosevelt (D–New York), running with Secretary of Agriculture Henry A. Wallace, with 52.27% of the popular vote, against Wendell Willkie (R–Indiana), running with Minority Leader Charles L. McNary, with 47.50% of the popular vote.[3][4]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | Franklin D. Roosevelt (inc.) | 958,476 | 52.27% | |
| Republican | Wendell Willkie | 871,009 | 47.50% | |
| Write-in | 4,244 | 0.23% | ||
| Total votes | 1,833,729 | 100% | ||
References
- ^ "United States Presidential election of 1940 - Encyclopædia Britannica". Retrieved August 21, 2018.
- ^ "1940 Election for the Thirty-ninth Term (1941-45)". Retrieved August 21, 2018.
- ^ "1940 Presidential General Election Results - Missouri". Retrieved August 21, 2018.
- ^ "The American Presidency Project - Election of 1940". Retrieved August 21, 2018.
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