1852 United States presidential election in Arkansas
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Elections in Arkansas |
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The 1852 United States presidential election in Arkansas took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.
Arkansas voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Arkansas by a margin of 24.36%.
Results
[edit]1852 United States presidential election in Arkansas[1][2] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | Franklin Pierce of New Hampshire | William R. King of Alabama | 12,173 | 62.18% | 4 | 100.00% | ||
Whig | Winfield Scott of New Jersey | William A. Graham of North Carolina | 7,404 | 37.82% | 0 | 0.00% | ||
Total | 19,577 | 100.00% | 4 | 100.00% |
See also
[edit]References
[edit]- ^ "1852 Presidential General Election Results - Arkansas". U.S. Election Atlas. Retrieved December 1, 2017.
- ^ "1852 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved December 1, 2017.