1892 United States presidential election in Kentucky
Appearance
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Elections in Kentucky |
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The 1892 United States presidential election in Kentucky took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. Kentucky voters chose thirteen electors to the Electoral College, which selected the president and vice president.
Kentucky was won by the Democratic nominees, former President Grover Cleveland of New York and his running mate Adlai Stevenson I of Illinois.
Results
United States presidential election in Kentucky, 1892[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Grover Cleveland | 175,461 | 51.48% | 13 | |
Republican | Benjamin Harrison (incumbent) | 135,462 | 39.74% | 0 | |
People's | James Weaver | 23,500 | 6.89% | 0 | |
Prohibition | John Bidwell | 6,441 | 1.89% | 0 | |
Totals | 340,864 | 100.00% | 13 | ||
Voter turnout | — |
References
- ^ Dave Leip’s U.S. Election Atlas; Presidential General Election Results – Kentucky